Edition Chapter 3 — Solution Manual Heat And Mass Transfer Cengel 5th

$T_{c}=T_{s}+\frac{P}{4\pi kL}$

$r_{o}=0.04m$

$\dot{Q} {net}=\dot{Q} {conv}+\dot{Q} {rad}+\dot{Q} {evap}$ $T_{c}=T_{s}+\frac{P}{4\pi kL}$ $r_{o}=0

$h=\frac{Nu_{D}k}{D}=\frac{10 \times 0.025}{0.004}=62.5W/m^{2}K$ $T_{c}=T_{s}+\frac{P}{4\pi kL}$ $r_{o}=0