Cs50 Tideman Solution -

candidate_t *candidates_list = malloc(candidates * sizeof(candidate_t)); for (int i = 0; i < candidates; i++) { candidates_list[i].id = i + 1; }

3 3 1 2 3 1 3 2 2 1 3 This input represents an election with 3 voters and 3 candidates. The output of the program should be:

winner = check_for_winner(candidates_list, candidates); } Cs50 Tideman Solution

The CS50 Tideman solution implements a voting system that determines the winner of an election based on ranked ballots. The solution involves reading input, initializing data structures, counting first-place votes, checking for a winner, eliminating candidates, and recounting votes. The implementation includes test cases to verify its correctness.

int main() { int voters, candidates; voter_t *voters_prefs; read_input(&voters, &candidates, &voters_prefs); The implementation includes test cases to verify its

recount_votes(voters_prefs, voters, candidates_list, candidates);

int winner = check_for_winner(candidates_list, candidates); while (winner == -1) { // Eliminate candidate with fewest votes int eliminated = -1; int min_votes = voters + 1; for (int i = 0; i < candidates; i++) { if (candidates_list[i].votes < min_votes) { min_votes = candidates_list[i].votes; eliminated = candidates_list[i].id; } } int winner = check_for_winner(candidates_list

return 0; } The implementation includes test cases to verify its correctness. For example, consider the following input: